\(\mathop {\lim }\limits_{x \to \infty } \left( {\frac{{x + \sin x}}{x}} \right)\) equals to

\(\mathop {\lim }\limits_{x \to \infty } \left( {\frac{{x + \sin x}}{x

1.	\(\mathop {\lim }\limits_{x \to \infty } \left( {\frac{{x + \sin x}}{x}} \right)\) equals to
A.	-∞
B.	0
C.	1
D.	∞
Answer» D. ∞

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\(\mathop {\lim }\limits_{x \to \infty } \left( {\frac{{x + \sin x}}{x}} \right)\) equals to

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