\(\mathop {\lim }\limits_{x \to 0} \frac{{\cos x - 1}}{{\sin x - x}}\) is equal to

\(\mathop {\lim }\limits_{x \to 0} \frac{{\cos x - 1}}{{\sin x - x}}\)

1.	\(\mathop {\lim }\limits_{x \to 0} \frac{{\cos x - 1}}{{\sin x - x}}\) is equal to
A.	Undefined
B.	∞
C.	1
D.	0
Answer» C. 1

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\(\mathop {\lim }\limits_{x \to 0} \frac{{\cos x - 1}}{{\sin x - x}}\) is equal to

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