Match List I with List IIList I(Configuration)List II(Equation of Base current)(a) Fixed Bias(i) $I_B = \frac{V_{CC}-V_{BE}}{R_B+(\beta + 1)R_E}$(b) Emitter Bias(ii) $I_B = \frac{V_{EE}-V_{BE}}{R_B+(\beta + 1)R_E}$(c) Emitter follower(iii) $I_B = \frac{V_{CC}-V_{BE}}{R_B}$(d) Common-base(iv) $I_B = \frac{V_{EE}-V_{BE}}{R_E+(\beta + 1)}$ Choose the correct answer from the options given below:

Question

Match List I with List IIList I(Configuration)List II(Equation of Base current)(a) Fixed Bias(i) $I_B = \frac{V_{CC}-V_{BE}}{R_B+(\beta + 1)R_E}$(b) Emitter Bias(ii) $I_B = \frac{V_{EE}-V_{BE}}{R_B+(\beta + 1)R_E}$(c) Emitter follower(iii) $I_B = \frac{V_{CC}-V_{BE}}{R_B}$(d) Common-base(iv) $I_B = \frac{V_{EE}-V_{BE}}{R_E+(\beta + 1)}$ Choose the correct answer from the options given below:

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

(a) - (ii), (b) - (iii), (c) - (i), (d) - (iv)

TuteeHUB · Answer

(a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)

TuteeHUB · Answer

(a) - (iii), (b) - (ii), (c) - (iv), (d) - (i)

TuteeHUB · Answer

(a) - (iii), (b) - (i), (c) - (ii), (d) - (iv)

1.	Match List I with List IIList I(Configuration)List II(Equation of Base current)(a) Fixed Bias(i) \(I_B = \frac{V_{CC}-V_{BE}}{R_B+(\beta + 1)R_E}\)(b) Emitter Bias(ii) \(I_B = \frac{V_{EE}-V_{BE}}{R_B+(\beta + 1)R_E}\)(c) Emitter follower(iii) \(I_B = \frac{V_{CC}-V_{BE}}{R_B}\)(d) Common-base(iv) \(I_B = \frac{V_{EE}-V_{BE}}{R_E+(\beta + 1)}\) Choose the correct answer from the options given below:
A.	(a) - (ii), (b) - (iii), (c) - (i), (d) - (iv)
B.	(a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)
C.	(a) - (iii), (b) - (ii), (c) - (iv), (d) - (i)
D.	(a) - (iii), (b) - (i), (c) - (ii), (d) - (iv)
Answer» E.

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