Let \(g\left( x \right) = \left\{ {\begin{array}{*{20}{c}} { - x,}&{x \le 1}\\ {x + 1,}&{x \ge 1} \end{array}} \right.\) and \(f\left( x \right) = \left\{ {\begin{array}{*{20}{c}} {1 - x,}&{x \le 0}\\ {{x^2},}&{x > 0} \end{array}} \right.\).Consider the composition of f and g, i.e. (fog)(x) = f(g(x)). The number of discontinuities in (fog)(x) present in the interval (-∞, 0) is:

Let \(g\left( x \right) = \left\{ {\begin{array}{*{20}{c}} { - x,}&{x

1.	Let \(g\left( x \right) = \left\{ {\begin{array}{{20}{c}} { - x,}&{x \le 1}\\ {x + 1,}&{x \ge 1} \end{array}} \right.\) and \(f\left( x \right) = \left\{ {\begin{array}{{20}{c}} {1 - x,}&{x \le 0}\\ {{x^2},}&{x > 0} \end{array}} \right.\).Consider the composition of f and g, i.e. (fog)(x) = f(g(x)). The number of discontinuities in (fog)(x) present in the interval (-∞, 0) is:
A.	0
B.	1
C.	2
D.	4
Answer» B. 1

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