Let \(f\left( x \right) = \left\{ {\begin{array}{*{20}{c}}{ - 1,}&{ - 2 \le x < 0}\\{{x^2} - 1,}&{0 \le x \le 2}\end{array}} \right.\) and g(x) = |f(x)| + f(|x|). Then in the interval (-2, 2), g is:

Not differentiable at two points

Not differentiable at one point

Let \(f\left( x \right) = \left\{ {\begin{array}{*{20}{c}}{ - 1,}&{ -

1.	Let \(f\left( x \right) = \left\{ {\begin{array}{*{20}{c}}{ - 1,}&{ - 2 \le x < 0}\\{{x^2} - 1,}&{0 \le x \le 2}\end{array}} \right.\) and g(x) = \|f(x)\| + f(\|x\|). Then in the interval (-2, 2), g is:
A.	Differentiable at all points
B.	Not continuous
C.	Not differentiable at two points
D.	Not differentiable at one point
Answer» E.

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Let \(f\left( x \right) = \left\{ {\begin{array}{*{20}{c}}{ - 1,}&{ - 2 \le x < 0}\\{{x^2} - 1,}&{0 \le x \le 2}\end{array}} \right.\) and g(x) = |f(x)| + f(|x|). Then in the interval (-2, 2), g is:

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