Let f be a function defined on the interval [0, 1] as \(f(x)=\left\lbrace \begin{matrix} 0, \ \text{if} \ x \ \text{is rational} \\\ 1, \ \text{if} \ x \ \text{is irrational}\end{matrix}\right.\) Then f is -

May or may not be R - integrable on [0, 1]

Let f be a function defined on the interval [0, 1] as \(f(x)=\left\lb

1.	Let f be a function defined on the interval [0, 1] as \(f(x)=\left\lbrace \begin{matrix} 0, \ \text{if} \ x \ \text{is rational} \\\ 1, \ \text{if} \ x \ \text{is irrational}\end{matrix}\right.\) Then f is -
A.	Not R - integrable on [0, 1]
B.	R - integrable on [0, 1]
C.	May or may not be R - integrable on [0, 1]
D.	None of these
Answer» B. R - integrable on [0, 1]

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Let f be a function defined on the interval [0, 1] as \(f(x)=\left\lbrace \begin{matrix} 0, \ \text{if} \ x \ \text{is rational} \\\ 1, \ \text{if} \ x \ \text{is irrational}\end{matrix}\right.\) Then f is -

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