Large networks can be divided into sub-networks by means of a/an:

1.	Large networks can be divided into sub-networks by means of a/an:
A.	Single two-port model
B.	Interconnected two-port model
C.	Isolated two-port model
D.	Maximum 3 two-port model
Answer» C. Isolated two-port model

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In ABCD parameters, A and C are called
Match the following list: List - I List – II(a)z11(i)\({\left. {\frac{{{V_2}}}{{{I_2}}}} \right|_{~at~{I_1} = 0}}\)(b)h11(ii)\({\left. {\frac{{{V_1}}}{{{I_1}}}} \right|_{~at~{V_2} = 0}}\)(c)h22(iii)\({\left. {\frac{{{V_1}}}{{{I_1}}}} \right|_{~at~{I_2} = 0}}\)(d)z22(iv)\({\left. {\frac{{{I_2}}}{{{V_2}}}} \right|_{~at~{I_1} = 0}}\) Correct code is:
Find Z11.
ABCD parameters are used in analysis of ______.
Directions: The following items consist of two statements, one labeled as “Assertion(A)” and the other labeled as “Reason(R)”. You are to examine the two statements carefully and decide if the Assertion(A) and the Reason(R) are individually true and if so whether the reason is a correct explanation of the assertion. Select your answer to these items using the codes given below and mark your answer accordingly.Assertion (A): The Z parameters are open circuit parameters.Reason (R): The Z parameters may be measured at one terminal while the other terminal is open.
For a two-port network, the condition of Symmetry in terms of z-parameters is
Match the following Lists:List-IList-II(a) Open circuit parameters(i) \(\left[ {\begin{array}{*{20}{c}} {\frac{{{I_1}}}{{{V_1}}}}&{\frac{{{I_1}}}{{{V_2}}}}\\ {\frac{{{I_2}}}{{{V_1}}}}&{\frac{{{I_2}}}{{{V_2}}}} \end{array}} \right]\)(b) Short circuit parameters(ii) \(\left[ {\begin{array}{*{20}{c}} {\frac{{{V_1}}}{{{I_1}}}}&{\frac{{{V_1}}}{{{V_2}}}}\\ {\frac{{{I_2}}}{{{I_1}}}}&{\frac{{{I_2}}}{{{V_2}}}} \end{array}} \right]\)(c) Hybrid parameters(iii) \(\left[ {\begin{array}{*{20}{c}} {\frac{{{V_1}}}{{{V_2}}}}&{\frac{{{V_1}}}{{ - {I_2}}}}\\ {\frac{{{I_2}}}{{{V_2}}}}&{\frac{{{I_1}}}{{ - {I_2}}}} \end{array}} \right]\)(d) Transmission parameters(iv) \(\left[ {\begin{array}{*{20}{c}} {\frac{{{V_1}}}{{{I_1}}}}&{\frac{{{V_1}}}{{{I_2}}}}\\ {\frac{{{V_2}}}{{{I_1}}}}&{\frac{{{V_2}}}{{{I_2}}}} \end{array}} \right]\) Correct codes are:Code:
For any lossless, reciprocal three-port network, one port can be terminated in a reactance so that the other two ports are:
Large networks can be divided into sub-networks by means of a/an:
For a two-port network A = x1, B = x2, C = 1 / x2. For the network to be reciprocal, D is equal to

Large networks can be divided into sub-networks by means of a/an:

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