\[\int{\frac{{{(x+1)}^{2}}\,\,dx}{x({{x}^{2}}+1)}}\] is equal to [MP PET 2003]

\[{{\log }_{e}}\frac{1}{{{x}^{2}}+1}+c\]

\[{{\log }_{e}}x+2{{\tan }^{-1}}x+c\]

\[{{\log }_{e}}\frac{1}{{{x}^{2}}+1}+c\]

\[{{\log }_{e}}\{x({{x}^{2}}+1)\}+c\]

\[\int{\frac{{{(x+1)}^{2}}\,\,dx}{x({{x}^{2}}+1)}}\] is equal to [MP

1.	\[\int{\frac{{{(x+1)}^{2}}\,\,dx}{x({{x}^{2}}+1)}}\] is equal to [MP PET 2003]
A.	\[{{\log }_{e}}x+c\]
B.	\[{{\log }_{e}}x+2{{\tan }^{-1}}x+c\]
C.	\[{{\log }_{e}}\frac{1}{{{x}^{2}}+1}+c\]
D.	\[{{\log }_{e}}\{x({{x}^{2}}+1)\}+c\]
Answer» C. \[{{\log }_{e}}\frac{1}{{{x}^{2}}+1}+c\]