1.

\[\int_{{}}^{{}}{\frac{x-1}{{{(x+1)}^{3}}}{{e}^{x}}\ dx=}\] [IIT 1983; MP PET 1990]

A. \[\frac{-{{e}^{x}}}{{{(x+1)}^{2}}}+c\]
B. \[\frac{{{e}^{x}}}{{{(x+1)}^{2}}}+c\]
C. \[\frac{{{e}^{x}}}{{{(x+1)}^{3}}}+c\]
D. \[\frac{-{{e}^{x}}}{{{(x+1)}^{3}}}+c\]
Answer» C. \[\frac{{{e}^{x}}}{{{(x+1)}^{3}}}+c\]


Discussion

No Comment Found