In the figure given below A and D are fixed points, link AB rotates at a uniform angular velocity of 900 rev/min ccw, find angular velocity of CDin rad/s.Rab = 100mm, Bc = 450, distance of E from BC = 100mm, Cf= 75mm, CD = 275mm, AD =250mm, perpendicular DF = 17mm, perpendicular BE = 250mm.

In the figure given below A and D are fixed points, link AB rotates a

1.	In the figure given below A and D are fixed points, link AB rotates at a uniform angular velocity of 900 rev/min ccw, find angular velocity of CDin rad/s.Rab = 100mm, Bc = 450, distance of E from BC = 100mm, Cf= 75mm, CD = 275mm, AD =250mm, perpendicular DF = 17mm, perpendicular BE = 250mm.
A.	48.37
B.	48.77
C.	49.47
D.	45.37
Answer» D. 45.37

Discussion

No Comment Found

Related MCQs

The locus of which axis is known as axode?
A line drawn through an instantaneous centre and perpendicular to the plane of motion is called __________
Locus of all instantaneous centres is known as centrode.
The locus of the instantaneous centre relative to the body itself is called the _________
The locus of the instantaneous centre in space during a definite motion of the body is called the _________
In the figure given below A and D are fixed points, link AB rotates at a uniform angular velocity of 900 rev/min ccw, find angular velocity of CDin rad/s.Rab = 100mm, Bc = 450, distance of E from BC = 100mm, Cf= 75mm, CD = 275mm, AD =250mm, perpendicular DF = 17mm, perpendicular BE = 250mm.
In the figure given below A and D are fixed points, link AB rotates at a uniform angular velocity of 900 rev/min ccw, find angular velocity of BC in rad/s.Rab = 100mm, Bc = 450, distance of E from BC = 100mm, Cf= 75mm, CD = 275mm, AD =250mm, perpendicular DF = 17mm, perpendicular BE = 250mm.
In the figure given below A and D are fixed points, link AB rotates at a uniform angular velocity of 900 rev/min ccw, find instantaneous velocity of point F in m/s.Rab = 100mm, Bc = 450, distance of E from BC = 100mm, Cf= 75mm, CD = 275mm, AD =250mm, perpendicular DF = 17mm, perpendicular BE = 250mm.
Velocity of a point B in a link can be calculated by using the relationVb = Va – Vba.
In the figure given below A and D are fixed points, link AB rotates at a uniform angular velocity of 900 rev/min ccw, find the instantaneous velocity of point E in m/s.Rab = 100mm, Bc = 450, distance of E from BC = 100mm, Cf = 75mm, CD = 275mm, AD = 250mm, perpendicular DF = 17mm, perpendicular BE = 250mm.

In the figure given below A and D are fixed points, link AB rotates at a uniform angular velocity of 900 rev/min ccw, find angular velocity of CDin rad/s.Rab = 100mm, Bc = 450, distance of E from BC = 100mm, Cf= 75mm, CD = 275mm, AD =250mm, perpendicular DF = 17mm, perpendicular BE = 250mm.

Discussion

No Comment Found

Related MCQs

Reply to Comment