In the equation SQNR = 6.02b + 16.81 – \(20log_{10} ⁡\frac{R}{σ_x}\), for R = 6σx the equation becomes?

In the equation SQNR = 6.02b + 16.81 – \(20log_{10} ⁡\frac{R}{σ_

1.	In the equation SQNR = 6.02b + 16.81 – \(20log_{10} ⁡\frac{R}{σ_x}\), for R = 6σx the equation becomes?
A.	SQNR = 6.02b-1.25 dB
B.	SQNR = 6.87b-1.55 dB
C.	SQNR = 6.02b+1.25 dB
D.	SQNR = 6.87b+1.25 dB
Answer» D. SQNR = 6.87b+1.25 dB

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In the equation SQNR = 6.02b + 16.81 – \(20log_{10} ⁡\frac{R}{σ_x}\), for R = 6σx the equation becomes?
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In the equation SQNR = 6.02b + 16.81 – \(20log_{10} ⁡\frac{R}{σ_x}\), for R = 6σx the equation becomes?

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