In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 100cos (103t+π/2), resistance R = 20Ω and inductance L = 0.1H. The particular integral of the solution of ‘ip’ is?

• A. ip = 0.98cos⁡(1000t+π/2-78.6o)
• B. ip = 0.98cos⁡(1000t-π/2-78.6o)
• C. ip = 0.98cos⁡(1000t-π/2+78.6o)
• D. ip = 0.98cos⁡(1000t+π/2+78.6o)