MCQOPTIONS
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MCQOPTIONS
| 1. |
In the above circuit, ID is |
| A. | \({I_D} = {I_{DSS}}{\left( {1 - \frac{{{V_{GS}}}}{{{V_{GS\left( {off} \right)}}}}} \right)^2}\) |
| B. | \({I_D} = {I_{DSS}}\left( {1 - \frac{{{V_{GS}}}}{{{V_{GS\left( {off} \right)}}}}} \right)\) |
| C. | \({I_D} = {I_{DSS}}\left( {1 - \frac{{{V_{GS}}}}{{{V_{DS\left( {off} \right)}}}}} \right)\) |
| D. | \({I_D} = {I_{DSS}}{\left( {1 - \frac{{{V_{GS}}}}{{{V_{DS\left( {off} \right)}}}}} \right)^2}\) |
| Answer» B. \({I_D} = {I_{DSS}}\left( {1 - \frac{{{V_{GS}}}}{{{V_{GS\left( {off} \right)}}}}} \right)\) | |