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				| 1. | In differential amplifier the input are given as V1=30sin⁡Π(50t)+10sin⁡Π(25t) , V2=30sin⁡Π(50t)-10 sin⁡Π(25t), β0 =200,RE =1kΩ and RC = 15kΩ. Find the output voltages V01, V02 & gm=4MΩ-1$ | 
| A. | V<sub>01</sub>=-60[10 sin⁡Π(25t) ]-6.637[30sin⁡Π(50t) ], V<sub>02</sub>=60[10 sin⁡Π(25t) ]-6.637[30sin⁡Π(50t) ]. | 
| B. | V<sub>01</sub>=-6.637[10 sin⁡Π(25t) ]-60[30sin⁡Π(50t) ], V<sub>02</sub>=6.637[10 sin⁡Π(25t) ]-60[30sin⁡Π(50t) ]. | 
| C. | V<sub>01</sub>=-60[30 sin⁡Π(50t) ]-6.637[10sin⁡Π(25t) ], V<sub>02</sub>=60[30 sin⁡Π(50t) ]-6.637[10sin⁡Π(25t) ]. | 
| D. | V<sub>01</sub>=-6.637[30 sin⁡Π(50t) ]-60[10sin⁡Π(25t) ], V<sub>02</sub>=6.637[30 sin⁡Π(50t) ]-60[10sin⁡Π(25t) ]. | 
| Answer» B. V<sub>01</sub>=-6.637[10 sin‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√≠‚Äö√тĆ(25t) ]-60[30sin‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√≠‚Äö√тĆ(50t) ], V<sub>02</sub>=6.637[10 sin‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√≠‚Äö√тĆ(25t) ]-60[30sin‚Äö√Ñ√∂‚àö√ñ¬¨‚àû‚âà√≠‚Äö√тĆ(50t) ]. | |