In an RLC series circuit, if the inductive reactance voltage exceeds t – McqOptions

MCQOPTIONS

1.	In an RLC series circuit, if the inductive reactance voltage exceeds the capacitive reactance voltage, the reactive component of power will:
A.	be in-phase with the current
B.	lead the current by 90°
C.	lag the current by 90°
D.	lead the voltage by 90°
Answer» D. lead the voltage by 90°

Discussion

No Comment Found

Related MCQs

Q = 2000 VAR, pf = 0.9 (leading). The power in complex form is
P = 269 W, Q = 150 VAR (capacitive). The power in the complex form is
In a two element series circuit, the applied voltage and the resulting current are v(t) = 60 + 66 sin (1000t) V, i(t) = 2.3sin (1000t + 68.3) 3 A. The nature of the elements would be
In the bridge shown, Z1 = 300 ohm, Z2 = 400 – j300 ohm, Z3 = 200 + j100 ohm. The Z4 at balance isa) 400 + j300 ohmb) 400 – j300 ohmc) j100 ohmd) -j900 ohm Circuit for Q.6 and Q.76. i1(t) = ?
Vc(t) = ?
i(t) = ?
Given V1 = 25∠0° V and V2 = 10∠36.87° V are connected in series. Find the resultant voltage Vs = V1 + V2.(Take cos 36.87° = 0.8, and sin 36.87° = 0.6)
In the circuit shown in the figure, the value of node voltage
In an RLC series circuit, if the inductive reactance voltage exceeds the capacitive reactance voltage, the reactive component of power will:
In a purely inductive circuit the current ______ the voltage by _______.