In a rolling operation, the thickness of a rectangular piece is reduced from t1 to t2. The radius of both the rolls are equal to R. The angle of bite (θ) will be given by:

Question

TuteeHUB · Accepted Answer

$\theta = {\cos ^{ - 1}}\left[ {\frac{{{t_1} - {t_2}}}{{2R}}} \right]$

TuteeHUB · Answer

$\theta = {\cos ^{ - 1}}\left[ {1 - \frac{{{t_1} - {t_2}}}{{2R}}} \right]$

TuteeHUB · Answer

$\theta = {\cos ^{ - 1}}\left[ {1 - \frac{{2R}}{{{t_1} - {t_2}}}} \right]$

TuteeHUB · Answer

$\theta = {\cos ^{ - 1}}\left[ {\frac{{2R}}{{{t_1} - {t_2}}}} \right]$

1.	In a rolling operation, the thickness of a rectangular piece is reduced from t1 to t2. The radius of both the rolls are equal to R. The angle of bite (θ) will be given by:
A.	\(\theta = {\cos ^{ - 1}}\left[ {1 - \frac{{{t_1} - {t_2}}}{{2R}}} \right]\)
B.	\(\theta = {\cos ^{ - 1}}\left[ {\frac{{{t_1} - {t_2}}}{{2R}}} \right]\)
C.	\(\theta = {\cos ^{ - 1}}\left[ {1 - \frac{{2R}}{{{t_1} - {t_2}}}} \right]\)
D.	\(\theta = {\cos ^{ - 1}}\left[ {\frac{{2R}}{{{t_1} - {t_2}}}} \right]\)
Answer» B. \(\theta = {\cos ^{ - 1}}\left[ {\frac{{{t_1} - {t_2}}}{{2R}}} \right]\)

In a rolling operation, the thickness of a rectangular piece is reduced from t1 to t2. The radius of both the rolls are equal to R. The angle of bite (θ) will be given by:

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