In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT = k, where k is a constant. In this process, the temperature of the gas is increased by ∆T. The amount of heat absorbed by gas is (where, R is gas constant)

\({\rm{\;}}\frac{{2k}}{3}\Delta T\)

In a process, temperature and volume of one mole of an ideal monoatomi

1.	In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT = k, where k is a constant. In this process, the temperature of the gas is increased by ∆T. The amount of heat absorbed by gas is (where, R is gas constant)
A.	\(\frac{1}{2}kR\Delta T\)
B.	\({\rm{\;}}\frac{{2k}}{3}\Delta T\)
C.	\(\frac{1}{2}R\Delta T\)
D.	\(\frac{3}{2}R\Delta T\)
Answer» D. \(\frac{3}{2}R\Delta T\)

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In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT = k, where k is a constant. In this process, the temperature of the gas is increased by ∆T. The amount of heat absorbed by gas is (where, R is gas constant)

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