

MCQOPTIONS
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1. |
If \[y={{x}^{{{x}^{x......\infty }}}}\], then \[\frac{dy}{dx}=\] [UPSEAT 2004; DCE 2000] |
A. | \[\frac{{{y}^{2}}}{x(1+y\log x)}\] |
B. | \[\frac{{{y}^{2}}}{x(1-y\log x)}\] |
C. | \[\frac{y}{x(1+y\log x)}\] |
D. | \[\frac{y}{x(1-y\log x)}\] |
Answer» C. \[\frac{y}{x(1+y\log x)}\] | |