If y = y(x) is the solution of the differential equation \(\frac{dy}{dx}=\left( tanx-y \right)se{{c}^{2}}x,~x\in \left( -\frac{\pi }{2},\frac{\pi }{2} \right)\) such that y(0) = 0, then \(y\left( -\frac{\pi }{4} \right)\) is equal to:

If y = y(x) is the solution of the differential equation \(\frac{dy}{d

1.	If y = y(x) is the solution of the differential equation \(\frac{dy}{dx}=\left( tanx-y \right)se{{c}^{2}}x,~x\in \left( -\frac{\pi }{2},\frac{\pi }{2} \right)\) such that y(0) = 0, then \(y\left( -\frac{\pi }{4} \right)\) is equal to:
A.	e - 2
B.	\(\frac{1}{2}-e\)
C.	\(2+\frac{1}{e}\)
D.	\(\frac{1}{e}-2\)
Answer» B. \(\frac{1}{2}-e\)

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If y = y(x) is the solution of the differential equation \(\frac{dy}{dx}=\left( tanx-y \right)se{{c}^{2}}x,~x\in \left( -\frac{\pi }{2},\frac{\pi }{2} \right)\) such that y(0) = 0, then \(y\left( -\frac{\pi }{4} \right)\) is equal to:

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