MCQOPTIONS
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| 1. |
If y = |sin x||x| then what is the value of \(\frac{{dy}}{{dx}}{\rm{\;}}at{\rm{\;}}x = {\rm{\;}} - \frac{\pi }{6}?\) |
| A. | \(\frac{{{2^{ - \frac{\pi }{6}}}\left( {6\ln 2 - \sqrt {3\pi } } \right)}}{6}\) |
| B. | \(\frac{{{2^{\frac{\pi }{6}}}\left( {6{\rm{\;}}ln2 + \sqrt 3 \pi } \right)}}{6}\) |
| C. | \(\frac{{{2^{ - \frac{\pi }{6}}}\left( {6{\rm{\;}}ln2 + \sqrt 3 \pi } \right)}}{6}\) |
| D. | \(\frac{{{2^{\frac{\pi }{6}}}\left( {6{\rm{\;}}ln2 - \sqrt 3 \pi } \right)}}{6}\) |
| Answer» B. \(\frac{{{2^{\frac{\pi }{6}}}\left( {6{\rm{\;}}ln2 + \sqrt 3 \pi } \right)}}{6}\) | |