1.

If x = a(Cos(t) + t2) and y = a(Sin(t) + t2 + t3) then dy/dx equals to

A. (Cos(t) + 3t<sup>2</sup> + 2t) / (-Sin(t) + 2t)
B. (Sin(t) + 3t<sup>2</sup> + 2t) / (-Cos(t) + 2t)
C. (Sin(t) + 3t<sup>2</sup> + 2t) / (Cos(t) + 2t)
D. (Cos(t) + 3t<sup>2</sup> + 2t) / (Sin(t) + 2t)
Answer» B. (Sin(t) + 3t<sup>2</sup> + 2t) / (-Cos(t) + 2t)


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