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1. |
If we substitute the equation \(x_l (t)= u_c (t)+j u_s (t)\) in equation x (t) + j ẋ (t) = xl(t) ej2πFct and equate real and imaginary parts on side, then what are the relations that we obtain? |
A. | x(t)=\(u_c (t) \,cos2π \,F_c \,t+u_s (t) \,sin2π \,F_c \,t\); ẋ(t)=\(u_s (t) \,cos2π \,F_c \,t-u_c \,(t) \,sin2π \,F_c \,t\) |
B. | x(t)=\(u_c (t) \,cos2π \,F_c \,t-u_s (t) \,sin2π \,F_c \,t\); ẋ(t)=\(u_s (t) \,cos2π \,F_c t+u_c (t) \,sin2π \,F_c \,t\) |
C. | x(t)=\(u_c (t) \,cos2π \,F_c t+u_s (t) \,sin2π \,F_c \,t\); ẋ(t)=\(u_s (t) \,cos2π \,F_c t+u_c (t) \,sin2π \,F_c \,t\) |
D. | x(t)=\(u_c (t) \,cos2π \,F_c \,t-u_s (t) \,sin2π \,F_c \,t\); ẋ(t)=\(u_s (t) \,cos2π \,F_c \,t-u_c (t) \,sin2π \,F_c \,t\) |
Answer» C. x(t)=\(u_c (t) \,cos2π \,F_c t+u_s (t) \,sin2π \,F_c \,t\); ẋ(t)=\(u_s (t) \,cos2π \,F_c t+u_c (t) \,sin2π \,F_c \,t\) | |