If U∞ = free stream velocity, u = velocity at y, and δ = boundary layer thickness, then in a boundary layer flow, the momentum thickness θ is given by

\(\theta = \mathop \smallint \limits_0^\delta \frac{u}{{{U_\infty }}}\left( {1 - \frac{{{u^2}}}{{U_\infty ^2}}} \right)dy\)

\(\theta = \mathop \smallint \limits_0^\delta \frac{u}{{{U_\infty }}}\left( {1 - \frac{u}{{{U_\infty }}}} \right)dy\)

\(\theta = \mathop \smallint \limits_0^\delta \frac{{{u^2}}}{{U_\infty ^2}}\left( {1 - \frac{u}{{{U_\infty }}}} \right)dy\)

\(\theta = \mathop \smallint \limits_0^\delta \left( {1 - \frac{u}{{{U_\infty }}}} \right)dy\)

If U∞ = free stream velocity, u = velocity at y, and δ = boundary l

1.	If U∞ = free stream velocity, u = velocity at y, and δ = boundary layer thickness, then in a boundary layer flow, the momentum thickness θ is given by
A.	\(\theta = \mathop \smallint \limits_0^\delta \frac{u}{{{U_\infty }}}\left( {1 - \frac{u}{{{U_\infty }}}} \right)dy\)
B.	\(\theta = \mathop \smallint \limits_0^\delta \frac{u}{{{U_\infty }}}\left( {1 - \frac{{{u^2}}}{{U_\infty ^2}}} \right)dy\)
C.	\(\theta = \mathop \smallint \limits_0^\delta \frac{{{u^2}}}{{U_\infty ^2}}\left( {1 - \frac{u}{{{U_\infty }}}} \right)dy\)
D.	\(\theta = \mathop \smallint \limits_0^\delta \left( {1 - \frac{u}{{{U_\infty }}}} \right)dy\)
Answer» B. \(\theta = \mathop \smallint \limits_0^\delta \frac{u}{{{U_\infty }}}\left( {1 - \frac{{{u^2}}}{{U_\infty ^2}}} \right)dy\)

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If U∞ = free stream velocity, u = velocity at y, and δ = boundary layer thickness, then in a boundary layer flow, the momentum thickness θ is given by

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