If the S parameters of a transistor given areS11=-0.811-j0.311S12= 0.0306+j0.0048S21=2.06+j3.717S22=-0.230-j0.4517Then ∆ for the given transistor is:

If the S parameters of a transistor given areS11=-0.811-j0.311S12= 0.

1.	If the S parameters of a transistor given areS11=-0.811-j0.311S12= 0.0306+j0.0048S21=2.06+j3.717S22=-0.230-j0.4517Then ∆ for the given transistor is:
A.	0.336
B.	0.383
C.	0.456
D.	None of the mentioned
Answer» B. 0.383

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By performing the K-∆ test for a given transistor the values of K and ∆ were found to be equal to 0.383 and 0.334 respectively. The transistor with these parameters has unconditional stability.
If the S parameters of a transistor given areS11=-0.811-j0.311S12= 0.0306+j0.0048S21=2.06+j3.717S22=-0.230-j0.4517Then ∆ for the given transistor is:
The condition for unconditional stability of a transistor as per the K-∆ test is │∆│> 1 and K
For any passive source termination ГS, Unconditional stability implies that:
If │S11│>1 or │S22│>1, the amplifier cannot be unconditionally stable.
By_performing_the_K-‚Äö√Ñ√∂‚àö‚Ä†‚àö√∫_test_for_a_given_transistor_the_values_of_K_and_‚Äö√Ñ√∂‚àö‚Ä†‚àö√∫_were_found_to_be_equal_to_0.383_and_0.334_respectively._The_transistor_with_these_parameters_has_unconditional_stability.$#
The condition for unconditional stability of a transistor as per the K-‚Äö√Ñ√∂‚àö‚Ä†‚àö√∫ test is ‚Äö√Ñ√∂‚àö√Ü‚àö√°‚Äö√Ñ√∂‚àö‚Ä†‚àö√∫‚Äö√Ñ√∂‚àö√Ü‚àö√°> 1 and K
For any passive source termination ‚Äö√Ñ√¨‚àö¬®S, Unconditional stability implies that:$
If ‚Äö√Ñ√∂‚àö√Ü‚àö√°S11‚Äö√Ñ√∂‚àö√Ü‚àö√°>1 or ‚Äö√Ñ√∂‚àö√Ü‚àö√°S22‚Äö√Ñ√∂‚àö√Ü‚àö√°>1, the amplifier cannot be unconditionally stable.$
For a unilateral device condition for unconditional stability in terms of S parameters is:

If the S parameters of a transistor given areS11=-0.811-j0.311S12= 0.0306+j0.0048S21=2.06+j3.717S22=-0.230-j0.4517Then ∆ for the given transistor is:

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