If the line, \(\frac{{x - 1}}{2} = \frac{{y + 1}}{3} = \frac{{z - 2}}{4}{\rm{\;}}\) meets the plane, \(x + 2y + 3z = 15{\rm{\;}}\) at a point P, then the distance of P from the origin is:

If the line, \(\frac{{x - 1}}{2} = \frac{{y + 1}}{3} = \frac{{z - 2}}

1.	If the line, \(\frac{{x - 1}}{2} = \frac{{y + 1}}{3} = \frac{{z - 2}}{4}{\rm{\;}}\) meets the plane, \(x + 2y + 3z = 15{\rm{\;}}\) at a point P, then the distance of P from the origin is:
A.	\(\frac{{\sqrt 5 }}{2}\)
B.	\(2\sqrt 5\)
C.	\(\frac{9}{2}\)
D.	\(\frac{7}{2}\)
Answer» D. \(\frac{7}{2}\)

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If the line, \(\frac{{x - 1}}{2} = \frac{{y + 1}}{3} = \frac{{z - 2}}{4}{\rm{\;}}\) meets the plane, \(x + 2y + 3z = 15{\rm{\;}}\) at a point P, then the distance of P from the origin is:

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