If the centre of a circle is (-6, 8) and it passes through the origin, then equation to its tangent at the origin is

If the centre of a circle is (-6, 8) and it passes through the origin,

1.	If the centre of a circle is (-6, 8) and it passes through the origin, then equation to its tangent at the origin is
A.	2y = x
B.	4y = 3x
C.	3y = 4x
D.	3x + 4y = 0
Answer» C. 3y = 4x

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If the centre of a circle is (-6, 8) and it passes through the origin, then equation to its tangent at the origin is

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