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1. |
If Sn=4Sn-1+12n, where S0=6 and S1=7, find the solution for the recurrence relation. |
A. | an=7(2n)−29/6n6n |
B. | an=6(6n)+6/7n6n |
C. | an=6(3n+1)−5n |
D. | an=nn−2/6n6n |
Answer» C. an=6(3n+1)−5n | |