 
			 
			MCQOPTIONS
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				| 1. | If Sn=4Sn-1+12n, where S0=6 and S1=7, find the solution for the recurrence relation. | 
| A. | an=7(2n)−29/6n6n | 
| B. | an=6(6n)+6/7n6n | 
| C. | an=6(3n+1)−5n | 
| D. | an=nn−2/6n6n | 
| Answer» C. an=6(3n+1)−5n | |