If \(\smallint {x^5}{e^{ - 4{x^3}}}dx = \frac{1}{{48}}{e^{ - 4{x^3}}}f\left( x \right) + C\) where C is a constant of integration, then f(x) is equal to:

If \(\smallint {x^5}{e^{ - 4{x^3}}}dx = \frac{1}{{48}}{e^{ - 4{x^3}}}f

1.	If \(\smallint {x^5}{e^{ - 4{x^3}}}dx = \frac{1}{{48}}{e^{ - 4{x^3}}}f\left( x \right) + C\) where C is a constant of integration, then f(x) is equal to:
A.	-2x3 - 1
B.	-4x3 - 1
C.	-2x3 + 1
D.	4x3 + 1
Answer» C. -2x3 + 1

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If \(\smallint {x^5}{e^{ - 4{x^3}}}dx = \frac{1}{{48}}{e^{ - 4{x^3}}}f\left( x \right) + C\) where C is a constant of integration, then f(x) is equal to:

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