If \(\smallint \frac{{x + 1}}{{\sqrt {2x - 1} }}{\rm{d}}x = f\left( x \right)\sqrt {2x - 1} + {\rm{C}}\), where C is a constant of integration, then f(x) is equal to:

\(\frac{1}{3}\left( {x + 1} \right)\)

\(\frac{2}{3}\left( {x + 2} \right)\)

\(\frac{2}{3}\left( {x - 4} \right)\)

\(\frac{1}{3}\left( {x + 4} \right)\)

If \(\smallint \frac{{x + 1}}{{\sqrt {2x - 1} }}{\rm{d}}x = f\left( x

1.	If \(\smallint \frac{{x + 1}}{{\sqrt {2x - 1} }}{\rm{d}}x = f\left( x \right)\sqrt {2x - 1} + {\rm{C}}\), where C is a constant of integration, then f(x) is equal to:
A.	\(\frac{1}{3}\left( {x + 1} \right)\)
B.	\(\frac{2}{3}\left( {x + 2} \right)\)
C.	\(\frac{2}{3}\left( {x - 4} \right)\)
D.	\(\frac{1}{3}\left( {x + 4} \right)\)
Answer» E.

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If \(\smallint \frac{{x + 1}}{{\sqrt {2x - 1} }}{\rm{d}}x = f\left( x \right)\sqrt {2x - 1} + {\rm{C}}\), where C is a constant of integration, then f(x) is equal to:

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