1.

If \(\sin {\rm{\theta }} = \frac{{{{\rm{P}}^2} - 1}}{{{{\rm{P}}^2} + 1}},\) then cos θ is equal to:

A. \(\frac{{2{\rm{P}}}}{{1 + {{\rm{P}}^2}}}\)
B. \(\frac{{\rm{P}}}{{{{\rm{P}}^2} - 1}}\)
C. \(\frac{{\rm{P}}}{{1 + {{\rm{P}}^2}}}\)
D. \(\frac{{2{\rm{P}}}}{{{{\rm{P}}^2} - 1}}\)
Answer» B. \(\frac{{\rm{P}}}{{{{\rm{P}}^2} - 1}}\)


Discussion

No Comment Found