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1. |
If \(\sin {\rm{\theta }} = \frac{{{{\rm{P}}^2} - 1}}{{{{\rm{P}}^2} + 1}},\) then cos θ is equal to: |
A. | \(\frac{{2{\rm{P}}}}{{1 + {{\rm{P}}^2}}}\) |
B. | \(\frac{{\rm{P}}}{{{{\rm{P}}^2} - 1}}\) |
C. | \(\frac{{\rm{P}}}{{1 + {{\rm{P}}^2}}}\) |
D. | \(\frac{{2{\rm{P}}}}{{{{\rm{P}}^2} - 1}}\) |
Answer» B. \(\frac{{\rm{P}}}{{{{\rm{P}}^2} - 1}}\) | |