MCQOPTIONS
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| 1. |
If secθ + tanθ = p, 0°< θ < 90°, then \(\frac{{{p^2} - 1}}{{{p^2} + 1}}\) is equal to: |
| A. | sin θ |
| B. | cosec θ |
| C. | cos θ |
| D. | 2 cosec θ |
| Answer» B. cosec θ | |