1.

If secθ + tanθ = m(>1), then the value of sinθ is (0° < θ < 90°)

A. $\frac{{1 - {m^2}}}{{1 + {m^2}}}$$
B. $\frac{{{m^2} - 1}}{{{m^2} + 1}}$$
C. $\frac{{{m^2} + 1}}{{{m^2} - 1}}$$
D. $\frac{{1 + {m^2}}}{{1 - {m^2}}}$$
Answer» C. $\frac{{{m^2} + 1}}{{{m^2} - 1}}$$


Discussion

No Comment Found

Related MCQs