If sec(5θ - 50°) = cosec(θ + 32°), then the value of θ is: (0° – McqOptions

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1.	If sec(5θ - 50°) = cosec(θ + 32°), then the value of θ is: (0°
A.	108°
B.	18°
C.	36°
D.	54°
Answer» C. 36°

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