If \({\rm{y}} = {\cot ^{ - 1}}\left[ {\frac{{\sqrt {1 + \sin {\rm{x}}} + \sqrt {1 - \sin {\rm{x}}} }}{{\sqrt {1 + \sin {\rm{x}}} - \sqrt {1 - \sin {\rm{x}}} }}} \right],\) where \(0 < {\rm{x}} < \frac{{\rm{\pi }}}{2}\), then \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\) is equal to

If \({\rm{y}} = {\cot ^{ - 1}}\left[ {\frac{{\sqrt {1 + \sin {\rm{x}}}

1.	If \({\rm{y}} = {\cot ^{ - 1}}\left[ {\frac{{\sqrt {1 + \sin {\rm{x}}} + \sqrt {1 - \sin {\rm{x}}} }}{{\sqrt {1 + \sin {\rm{x}}} - \sqrt {1 - \sin {\rm{x}}} }}} \right],\) where \(0 < {\rm{x}} < \frac{{\rm{\pi }}}{2}\), then \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\) is equal to
A.	\(\frac{1}{2}\)
B.	2
C.	sin x + cos x
D.	sin x – cos x
Answer» B. 2

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