If \(\rm \displaystyle\int\dfrac{xe^x}{\sqrt{1+e^x}}dx=f(x)\sqrt{1+e^x}- \rm 2 \log \frac{\sqrt{1+e^x}-1}{\sqrt{1+e^x}+1}+C\), then f(x) is

If \(\rm \displaystyle\int\dfrac{xe^x}{\sqrt{1+e^x}}dx=f(x)\sqrt{1+e^

1.	If \(\rm \displaystyle\int\dfrac{xe^x}{\sqrt{1+e^x}}dx=f(x)\sqrt{1+e^x}- \rm 2 \log \frac{\sqrt{1+e^x}-1}{\sqrt{1+e^x}+1}+C\), then f(x) is
A.	2x - 1
B.	2x - 4
C.	x + 4
D.	x - 4
Answer» C. x + 4

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If \(\rm \displaystyle\int\dfrac{xe^x}{\sqrt{1+e^x}}dx=f(x)\sqrt{1+e^x}- \rm 2 \log \frac{\sqrt{1+e^x}-1}{\sqrt{1+e^x}+1}+C\), then f(x) is

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