If Q(0, -1, -3) is the image of the point P in the plane 3x – y + 4z = 2 and R is the point (3, -1, -2), then the area (in sq. units) of ΔPQR is:

If Q(0, -1, -3) is the image of the point P in the plane 3x – y + 4z

1.	If Q(0, -1, -3) is the image of the point P in the plane 3x – y + 4z = 2 and R is the point (3, -1, -2), then the area (in sq. units) of ΔPQR is:
A.	2√13
B.	\(\frac{{\sqrt {91} }}{4}\)
C.	\(\frac{{\sqrt {91} }}{2}\)
D.	\(\frac{{\sqrt {65} }}{2}\)
Answer» D. \(\frac{{\sqrt {65} }}{2}\)

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If Q(0, -1, -3) is the image of the point P in the plane 3x – y + 4z = 2 and R is the point (3, -1, -2), then the area (in sq. units) of ΔPQR is:

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