If lines \(\frac {x-1}{-3} = \frac {y - 2}{2k} = \frac {z - 3}{2}\) and \(\frac {x-1}{3k} = \frac {y-5}{1}=\frac {z-6}{-5}\) are mutually perpendicular, then k is equal to-

If lines \(\frac {x-1}{-3} = \frac {y - 2}{2k} = \frac {z - 3}{2}\)

1.	If lines \(\frac {x-1}{-3} = \frac {y - 2}{2k} = \frac {z - 3}{2}\) and \(\frac {x-1}{3k} = \frac {y-5}{1}=\frac {z-6}{-5}\) are mutually perpendicular, then k is equal to-
A.	\(\frac {-10}{7}\)
B.	\(-\frac {7}{10}\)
C.	-10
D.	-7
Answer» B. \(-\frac {7}{10}\)

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If lines \(\frac {x-1}{-3} = \frac {y - 2}{2k} = \frac {z - 3}{2}\) and \(\frac {x-1}{3k} = \frac {y-5}{1}=\frac {z-6}{-5}\) are mutually perpendicular, then k is equal to-

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