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1. |
If $${\left( {r\cos \theta- \sqrt 3 } \right)^2}$$+ $${\left( {r\sin \theta- 1} \right)^2}$$= 0,then the value of $$\frac{{r\tan \theta+ \sec \theta }}{{r\sec \theta+ \tan \theta }}$$is equal to? |
A. | $\frac{4}{5}$$ |
B. | $\frac{3}{5}$$ |
C. | $\frac{{\sqrt 3 }}{4}$$ |
D. | $\frac{{\sqrt 5 }}{4}$$ |
Answer» B. $\frac{3}{5}$$ | |