If \(I_1 = \displaystyle\int_e^{e^2} \dfrac{dx}{\log x}\)and \(I_2 = \displaystyle\int_1^2 \dfrac{e^x}{x} dx\) then

If \(I_1 = \displaystyle\int_e^{e^2} \dfrac{dx}{\log x}\)and \(I_2 =

1.	If \(I_1 = \displaystyle\int_e^{e^2} \dfrac{dx}{\log x}\)and \(I_2 = \displaystyle\int_1^2 \dfrac{e^x}{x} dx\) then
A.	I1 - I2 = 0
B.	I2 = 2I1
C.	I1 = 2I2
D.	I1 + I2 = 0
Answer» B. I2 = 2I1

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If \(I_1 = \displaystyle\int_e^{e^2} \dfrac{dx}{\log x}\)and \(I_2 = \displaystyle\int_1^2 \dfrac{e^x}{x} dx\) then

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