If h(n) is causal and h(n)=he(n)+ho(n),then what is the expression for – McqOptions

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1.	If h(n) is causal and h(n)=h_e(n)+h_o(n),then what is the expression for h(n) in terms of only h_o(n)?
A.	h(n)=2h<sub>o</sub>(n)u(n)+h(0) (n), n 0
B.	h(n)=2h<sub>o</sub>(n)u(n)+h(0) (n), n 1
C.	h(n)=2h<sub>o</sub>(n)u(n)-h(0) (n), n 1
D.	h(n)=2h<sub>o</sub>(n)u(n)-h(0) (n), n 0
Answer» C. h(n)=2h<sub>o</sub>(n)u(n)-h(0) (n), n 1

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