If \(\frac{{1\; + \;\sin \phi }}{{1 - \sin \phi }} = \frac{{{p^2}}}{{{q^2}}}\), then sec ϕ is equal to∶

\(\frac{{{p^2}{q^2}}}{{{p^2} + {q^2}}}\)

\(\frac{1}{{{p^2}}} + \frac{1}{{{q^2}}}\)

\(\frac{1}{2}\left( {\frac{q}{p} + \frac{p}{q}} \right)\)

\(\frac{{2{p^2}{q^2}}}{{{p^2} + {q^2}}}\)

If \(\frac{{1\; + \;\sin \phi }}{{1 - \sin \phi }} = \frac{{{p^2}}}{{{

1.	If \(\frac{{1\; + \;\sin \phi }}{{1 - \sin \phi }} = \frac{{{p^2}}}{{{q^2}}}\), then sec ϕ is equal to∶
A.	\(\frac{1}{{{p^2}}} + \frac{1}{{{q^2}}}\)
B.	\(\frac{1}{2}\left( {\frac{q}{p} + \frac{p}{q}} \right)\)
C.	\(\frac{{{p^2}{q^2}}}{{{p^2} + {q^2}}}\)
D.	\(\frac{{2{p^2}{q^2}}}{{{p^2} + {q^2}}}\)
Answer» C. \(\frac{{{p^2}{q^2}}}{{{p^2} + {q^2}}}\)