If foci of a hyperbola are (0, 5) and length of semi transverse axis is 3 units, then find the equation of hyperbola.

(( frac{x}{3})^2-( frac{y}{4})^2 )=1

(( frac{x}{4})^2-( frac{y}{3})^2 )=1

(( frac{x}{3})^2-( frac{y}{4})^2 )=1

(( frac{x}{10})^2+( frac{y}{8})^2 )=1

(( frac{x}{8})^2-( frac{y}{6})^2 )=1

If foci of a hyperbola are (0, 5) and length of semi transverse axis

1.	If foci of a hyperbola are (0, 5) and length of semi transverse axis is 3 units, then find the equation of hyperbola.
A.	(( frac{x}{4})^2-( frac{y}{3})^2 )=1
B.	(( frac{x}{3})^2-( frac{y}{4})^2 )=1
C.	(( frac{x}{10})^2+( frac{y}{8})^2 )=1
D.	(( frac{x}{8})^2-( frac{y}{6})^2 )=1
Answer» B. (( frac{x}{3})^2-( frac{y}{4})^2 )=1

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