If eθϕ = c + 4θϕ, where c is an arbitrary constant and ϕ is a function of θ, then what is ϕ dθ equal to?

If eθϕ = c + 4θϕ, where c is an arbitrary constant and ϕ is a f

1.	If eθϕ = c + 4θϕ, where c is an arbitrary constant and ϕ is a function of θ, then what is ϕ dθ equal to?
A.	θ dϕ
B.	- θdϕ
C.	4θ dϕ
D.	-4θ dϕ
Answer» C. 4θ dϕ

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If eθϕ = c + 4θϕ, where c is an arbitrary constant and ϕ is a function of θ, then what is ϕ dθ equal to?

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