If \(\displaystyle\int \dfrac{(x - 1)^2}{(x^2 + 1)^2} dx = tan^{-1} x + g(x) + k,\)the g(x) =

If \(\displaystyle\int \dfrac{(x - 1)^2}{(x^2 + 1)^2} dx = tan^{-1} x

1.	If \(\displaystyle\int \dfrac{(x - 1)^2}{(x^2 + 1)^2} dx = tan^{-1} x + g(x) + k,\)the g(x) =
A.	None of these
B.	\(\dfrac{1}{2(x^2+1)}\)
C.	\(\dfrac{1}{(x^2+1)}\)
D.	\(tan^{-1} \dfrac{x}{2}\)
Answer» D. \(tan^{-1} \dfrac{x}{2}\)

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If \(\displaystyle\int \dfrac{(x - 1)^2}{(x^2 + 1)^2} dx = tan^{-1} x + g(x) + k,\)the g(x) =

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