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1. |
If a,d and Sn are first term, common difference and sum of first nth terms of series, then Sb = |
A. | n/2[2a+(n-1)d] |
B. | n/2[a+(n-1)d] |
C. | n/[2a+(n-1)d] |
D. | a+(n-1)d |
Answer» B. n/2[a+(n-1)d] | |