If 2sin2θ + 3sinθ – 2 = 0, (0° < θ < 90°) then the value of θ – McqOptions

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1.	If 2sin2θ + 3sinθ – 2 = 0, (0° < θ < 90°) then the value of θ is:
A.	90°
B.	30°
C.	45°
D.	60°
Answer» C. 45°

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