Fourier Transform of \(e^{-|x|} \, is \) \( \frac{2}{1+p^2} \). Then what is the fourier transform of \( e^{-2|x|} \)?

Fourier Transform of \(e^{-|x|} \, is \) \( \frac{2}{1+p^2} \). Then

1.	Fourier Transform of \(e^{-\|x\|} \, is \) \( \frac{2}{1+p^2} \). Then what is the fourier transform of \( e^{-2\|x\|} \)?
A.	\(\frac{4}{(4+p^2)} \)
B.	\(\frac{2}{(4+p^2)} \)
C.	\(\frac{2}{(2+p^2)} \)
D.	\(\frac{4}{(2+p^2)} \)
Answer» B. \(\frac{2}{(4+p^2)} \)