Find the Fourier Cosine Transform of F(x) = 2x for 0

Question

TuteeHUB · Accepted Answer

$fc(p) = \frac{32}{(p^2 π^2)} (cos(pπ)-1)p $ not equal to 0 and if equal to 0 $ fc(p) = 32 $

TuteeHUB · Answer

$fc(p) = \frac{32}{(p^2 π^2)} (cos(pπ)-1)p $ not equal to 0 and if equal to 0 $ fc(p) = 16 $

TuteeHUB · Answer

$fc(p) = \frac{32}{(p^2 π^2)} (cos(pπ)-1)p $ not equal to 0 and if equal to 0 $ fc(p) = 32 $

TuteeHUB · Answer

$fc(p) = \frac{64}{(pπ^2)} (cos(pπ)-1)p $ not equal to 0 and if equal to 0 $ fc(p) = 16 $

TuteeHUB · Answer

$fc(p) = \frac{32}{(pπ^2)} (cos(pπ)-1)p $ not equal to 0 and if equal to 0 $ fc(p) = 64 $

1.	Find the Fourier Cosine Transform of F(x) = 2x for 0
A.	\(fc(p) = \frac{32}{(p^2 π^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 16 \)
B.	\(fc(p) = \frac{32}{(p^2 π^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 32 \)
C.	\(fc(p) = \frac{64}{(pπ^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 16 \)
D.	\(fc(p) = \frac{32}{(pπ^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 64 \)
Answer» B. \(fc(p) = \frac{32}{(p^2 π^2)} (cos(pπ)-1)p \) not equal to 0 and if equal to 0 \( fc(p) = 32 \)

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