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1. |
For the given circuit, which one of the following is the correct state equation? |
A. | \(\frac{d}{{dt}}\left[ {\begin{array}{*{20}{c}} v\\ i \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} { - 4}&4\\ { - 2}&{ - 4} \end{array}} \right]\left[ {\begin{array}{*{20}{c}} v\\ i \end{array}} \right] + \left[ {\begin{array}{*{20}{c}} 0&4\\ 4&0 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {{i_1}}\\ {{i_2}} \end{array}} \right]\) |
B. | \(\frac{d}{{dt}}\left[ {\begin{array}{*{20}{c}} v\\ i \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} { - 4}&{ - 4}\\ { - 2}&4 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} v\\ i \end{array}} \right] + \left[ {\begin{array}{*{20}{c}} 4&4\\ 4&0 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {{i_1}}\\ {{i_2}} \end{array}} \right]\) |
C. | \(\frac{d}{{dt}}\left[ {\begin{array}{*{20}{c}} v\\ i \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} 4&{ - 4}\\ { - 2}&{ - 4} \end{array}} \right]\left[ {\begin{array}{*{20}{c}} v\\ i \end{array}} \right] + \left[ {\begin{array}{*{20}{c}} 0&4\\ 4&4 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {{i_1}}\\ {{i_2}} \end{array}} \right]\) |
D. | \(\frac{d}{{dt}}\left[ {\begin{array}{*{20}{c}} v\\ i \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} { - 4}&{ - 4}\\ { - 2}&{ - 4} \end{array}} \right]\left[ {\begin{array}{*{20}{c}} v\\ i \end{array}} \right] + \left[ {\begin{array}{*{20}{c}} 4&0\\ 0&4 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {{i_1}}\\ {{i_2}} \end{array}} \right]\) |
Answer» B. \(\frac{d}{{dt}}\left[ {\begin{array}{*{20}{c}} v\\ i \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} { - 4}&{ - 4}\\ { - 2}&4 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} v\\ i \end{array}} \right] + \left[ {\begin{array}{*{20}{c}} 4&4\\ 4&0 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} {{i_1}}\\ {{i_2}} \end{array}} \right]\) | |